⚖️ Three fruits, weighed two at a time

A closer look at one question · SMC 2024, Question 26 (bank id C1)

Mr Lee had an apple 🍎, a papaya 🫚 and a honeydew 🍈. He weighed them in PAIRS: apple + papaya = 730 g, apple + honeydew = 1960 g, honeydew + papaya = 2470 g. What was the mass of the honeydew?

1 Every fruit was weighed exactly TWICE

weighingmass
🍎 + 🫚 (apple + papaya)730 g
🍎 + 🍈 (apple + honeydew)1960 g
🍈 + 🫚 (honeydew + papaya)2470 g

Look closely: 🍎 appears twice, 🫚 appears twice, 🍈 appears twice. Adding all three rows counts every fruit's mass exactly twice over.

2 Add everything, then halve it

Sum
730 + 1960 + 2470 = 5160 g
÷ 2
🍎 + 🫚 + 🍈 together = 2580 g

3 Take off the ONE weighing that leaves honeydew out

"apple + papaya" (730 g) is the only weighing with no honeydew in it, so:

🍈
2580 − 730
1850 g

is the mass of the honeydew.

The trap: subtracting two of the weighings and hoping. Adding ALL THREE and halving is what turns three pair-weights into the single total — the rest is one subtraction.